Table: Person
+-------------+---------+| Column Name | Type |+-------------+---------+| PersonId | int || FirstName | varchar || LastName | varchar |+-------------+---------+PersonId is the primary key column for this table.
Table: Address
+-------------+---------+| Column Name | Type |+-------------+---------+| AddressId | int || PersonId | int || City | varchar || State | varchar |+-------------+---------+AddressId is the primary key column for this table.
Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:
FirstName, LastName, City, State
LeetCode还出了是来到数据库的题,来那么也来做做吧,这道题是第一道,相对来说比较简单,是一道两表联合查找的问题,我们需要用到Join操作,关于一些Join操作可以看我之前的博客,最直接的方法就是用Left Join来做,根据PersonId这项来把两个表联合起来:
解法一:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person LEFT JOIN Address ON Person.PersonId = Address.PersonId;
在使用Left Join时,我们也可以使用关键Using来声明我们相用哪个列名来进行联合:
解法二:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person LEFT JOIN Address USING(PersonId);
或者我们可以加上Natural关键字,这样我们就不用声明具体的列,MySQL可以自行搜索相同的列:
解法三:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person NATURAL LEFT JOIN Address;
参考资料: